Method on @infsup: minus (X, Y)

Operator on @infsup: X - Y

Subtract all numbers of interval Y from all numbers of X.

Accuracy: The result is a tight enclosure.

x = infsup (2, 3);
y = infsup (1, 2);
x - y
  ⇒ ans = [0, 2]

See also: @infsup/plus.

Package: interval