Method on @infsup: ldivide (X, Y)

Operator on @infsup: X .\ Y

Divide all numbers of interval Y by all numbers of X.

Accuracy: The result is a tight enclosure.

x = infsup (2, 3);
y = infsup (1, 2);
x .\ y
  ⇒ ans ⊂ [0.33333, 1]

See also: @infsup/times.

Package: interval