Compute the minimum value chosen from intervals.
This function does not return the least element of the interval (see
inf
), but returns an interval enclosure of the function:
min (x, y) = ( (x + y) - abs (x - y) ) / 2
With two arguments the function is applied element-wise. Otherwise the minimum is computed for all interval members along dimension DIM, which defaults to the first non-singleton dimension.
Accuracy: The result is a tight enclosure.
x = infsup (2, 3); y = infsup (1, 2); min (x, y) ⇒ ans = [1, 2]
See also: @infsup/max.
Package: interval