Method on @infsup: sup (X)

Get the (least) upper boundary for all numbers of interval X.

If X is empty, sup (X) is negative infinity.

Accuracy: The result is exact.

sup (infsup (2.5, 3.5))
  ⇒ ans = 3.5000

See also: @infsup/inf, @infsup/mid.

Package: interval